*NCERT Solutions For Class 10 Maths All Chapters:*

*NCERT Solutions For Class 10 Maths All Chapters:*

* NCERT class 10 math*-Get your India’s No.1

**Handwritten NCERT Class -10**Mathematics Solution in pdf format. All these solutions have been prepared by our Mathematics Specialist & experts, which has been prescribed by NCERT. With handwriting notes, you get help in presenting the answer sheet for the board and other exams.

*contains a total of 15 chapters which we have solved step by step for easy understanding of the solution, and at the end of each chapter important questions and quizzes are given for the practice approach of the exams.*

**NCERT solutions class 10 maths**You can download * ncert solutions class 10 maths PDF* for free and start your preparation to get maximum marks in upcoming and Board examinations.

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**NCERT**Solution Class 10 PDF helps you in your preparation with exercise differentiation so that you can read each chapter more easily and can come back to any chapter again if necessary.

**Contents:**

**Chapter 1 Real Numbers****Chapter 2 Polynomials****Chapter 3 Pair of Linear Equations in Two Variables****Chapter 4 Quadratic Equations****Chapter 5 Arithmetic Progressions****Chapter 6 Triangles****Chapter 7 Coordinate Geometry****Chapter 8 Introduction to Trigonometry****Chapter 9 Some Applications of Trigonometry****Chapter 10 Circles****Chapter 11 Constructions****Chapter 12 Areas Related to Circles****Chapter 13 Surface Areas and Volumes****Chapter 14 Statistics****Chapter 15 Probability**

**NCERT Solutions for Class 10 Maths Chapter 1 ( Real Numbers)**

**NCERT Solutions for Class 10 Maths Chapter 1 ( Real Numbers)**

** NCERT maths class 10 (ex 1)** Chapter

**1**Real Numbers for all boards. We have updated all the contents for the new academic session 2020-2021.In this chapter, you have studied the following points:

- Euclid’s division lemma :

Given positive integers a and b, there exist whole numbers q and r satisfying a = bq + r,

0 ≤ r < b. - Euclid’s division algorithm: This is based on Euclid’s division lemma. According to this,

the HCF of any two positive integers a and b, with a > b, is obtained as follows:

- Apply the division lemma to find q and r where a = bq + r, 0 ≤ r < b
- If r = 0, the HCF is b. If r ≠ 0, apply Euclid’s lemma to b and r.
- Continue the process till the remainder is zero. The divisor at this stage will be

HCF (a, b). Also, HCF(a, b) = HCF(b, r).

EXERCISE-1.1/ EXERCISE-1.2/ EXERCISE-1.3 / EXERCISE-1.4

*NCERT Solutions For Class 10 Math’s Chapter 9 (Some Applications of Trigonometry)*

**Math NCERT solution class 10****( class 10 maths ex 9.1) Chapter 9 Applications of Trigonometry **for all boards. We have updated all the contents for the new academic session 2020-2021.In this chapter, you have studied the following points:

- The line of sight is the line drawn from the point of view of the observer to the object seen by the observer.

- The angle of elevation of the observed object is the angle formed by the line of sight with the horizontal level when it is above the horizontal level, that is, when we raise our head to see the object.
- The angle of depression of an object is seen as the angle formed by the line of sight with the horizontal level when it is below the horizontal level, that is, when we lower our head to see the object.
- The height or length of an object or the distance between two distant objects can be determined with the help of trigonometric ratios.

#### EXERCISE-9.1

**NCERT Solutions For Class 10 Math’s Chapter 13 ****(Surface areas and volumes)**

**NCERT Solutions For Class 10 Math’s Chapter 13**

**(Surface areas and volumes)**

* NCERT Solutions for Class 10 Maths Chapter 13* Surface areas and volumes for all exercises for all boards. We have updated all the contents for the new academic session 2020-2021.From Class IX, you are familiar with some of the solids like cuboid, cone, cylinder, and sphere. You have also learned how to find their surface areas and volumes. In our day-to-day life, we come across a number of solids made up of combinations of two or more of the basic solids. In this exercise, you will see how to find surface areas and volumes of such objects.

EXERCISE-13.1 / EXERCISE-13.2 / EXERCISR-13.3 / EXERCISR-13.4 / EXERCISR-13.5

*NC**ERT** Solutions for Class 10 Maths Chapter 3 (***Pair of Linear Equations in Two Variables***)*

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*ERT*

*Solutions for Class 10 Maths Chapter 3 (*

*)*

**NCERT Solutions for Class 10 Maths Pair of Linear Equations in Two Variables of all exercise (NCERT maths class 10 ex 3) for all boards**. We have updated all the contents for the new academic session 2020-2021.You can download this PDF for free and start your preparation to get maximum marks in upcoming and Board examinations.

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**NCERT**Solution

** Exercise 3 Math Class 10** PDF helps you in your preparation with exercise differentiation so that you can read each chapter more easily and can come back to any chapter again if necessary.

**Introduction:**

NCERT Solutions for Class 10 Maths (Introduction) **Pair of Linear Equations in Two Variables of all exercise ( Class 10 Math ) **you have studied the following points:

- A pair of linear equations in two variables can be represented, and solved, by the:
- (i) graphical method (ii) algebraic method
- Graphical Method :

**The graph of a pair of linear equations in two variables is represented by two lines.**

(i) If the lines intersect at a point, then that point gives the unique solution of the two

equations. In this case, the pair of equations is consistent.

(ii) If the lines coincide, then there are infinitely many solutions — each point on the

line being a solution. In this case, the pair of equations is dependent (consistent).

(iii) If the lines are parallel, then the pair of equations has no solution. In this case, the

pair of equations is inconsistent.

**Algebraic Methods: We have discussed the following methods for finding the solution(s)**

**of a pair of linear equations :**

(i) Substitution Method

(ii) Elimination Method

(iii) Cross-multiplication Method

*NCERT Solutions for Class 10 Maths Chapter 6 *Triangles *(Class 10 Maths *) for all boards. We **have updated all the contents for the new academic session 2021-2022.**

*NCERT Solutions for Class 10 Maths Chapter 6*Triangles

Get free **NCERT Solutions for Class 10 Maths Chapter 6 Triangles** India’s No. 1 Handwritten (Like Class Notes) which provides a complete explanation of the exact and easy solution to all the problems covered in NCERT textbooks to the students of * Triangles class 10 *in PDF format, which is prepared by our subject qualified and experts in NCERT textbooks.

You can download this ** NCERT Maths class 10 PDF ** for free and start your preparation to get maximum marks in upcoming and Board examinations.

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**NCERT**Solution

**Class 10 Maths Chapter****6**PDF helps you in your preparation with exercise differentiation so that you can read each chapter more easily and can come back to any chapter again if necessary.

**NCERT Class 10th ****maths chapter 6** Pdf is Handwritten under the CBSE guidelines to help you score well in all upcoming exams.

### Math NCERT Solution Class 10

NCERT Math Class 10, Several important theorems are introduced which form the basis of mathematical concepts. Not only to score well in the board exams but also to build a strong foundation in the subject, it is necessary for the class 10 students to learn all the theorems thoroughly with statements and proofs. There are some important Theorem in NCERT Maths class 10 like * Pythagoras Theorem Formula*,

**Converse of****Pythagoras,***etc. which is often asked in exams.*

**BPT theorem****List of Important Class 10 Maths Theorems**

* Basic Proportionality Theorem or BPT (Theorem 6.1)*: If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.

* Converse of BPT Theorem (Theorem 6.2):* If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.

* Areas of Similar Triangles (Theorem 6.6): *The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

* Pythagoras Theorem (Theorem 6.8): *In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

* Converse of Pythagoras theorem (Theorem 6.9):* In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

**In this chapter you have studied the following points **

- If in two triangles, corresponding angles are equal, then their corresponding sides are in

the same ratio and hence the two triangles are similar (AAA similarity criterion) - If in two triangles, two angles of one triangle are respectively equal to the two angles of

the other triangle, then the two triangles are similar (AA similarity criterion). - In two triangles, corresponding sides are in the same ratio, then their corresponding

angles are equal and hence the triangles are similar (SSS similarity criterion). - If one angle of a triangle is equal to one angle of another triangle and the sides including

these angles are in the same ratio (proportional), then the triangles are similar

(SAS similarity criterion).

**Important Points:**

- All the congruent figures are similar but the converse is not true.
- Two polygons of the same number of sides are similar, if (i) their corresponding angles

are equal and (ii) their corresponding sides are in the same ratio (i.e., proportion). - Two polygons of the same number of sides are similar, if (i) their corresponding angles

are equal and (ii) their corresponding sides are in the same ratio (i.e., proportion). - If in a triangle, square of one side is equal to the sum of the squares of the other two

sides, then the angle opposite the first side is a right angle.

### Course Features

- Lectures 65
- Quizzes 0
- Duration 20 weeks
- Skill level All levels
- Language English
- Students 2
- Certificate No
- Assessments Self