# EXERCISE 5.1

*NC**ERT** Solutions for Class 10 Maths Chapter 5 ex 5.1 Arithmetic Progressions*

*NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions of exercise 5.1**(Class 10 Maths Ex 5.1*)** for all boards**. We have updated all the contents for the new academic session 2020-2021.

*NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions of exercise 5.1*

* Exercise 5.1 Class 10* -India’s No. 1 Handwritten (Like Class Notes) which provides a complete explanation of the exact and easy solution to all the problems covered in NCERT textbooks to the students of class 1

^{st}2

^{nd}3

^{rd}4

^{th}5

^{th}6

^{th}7

^{th}8

^{th}9

^{th}10

^{th}11

^{th}and 12

^{th}in PDF format, which is prepared by our subject qualified and experts in NCERT textbooks.

You can download this PDF for free and start your preparation to get maximum marks in upcoming and Board examinations. **Gicsu** **NCERT** Solution * (Math Class 10 Exercise 5.1) * PDF helps you in your preparation with exercise differentiation so that you can read each chapter more easily and can come back to any chapter again if necessary.

*NCERT Solutions for Class 10 Maths (Introduction)*

### Arithmetic Progressions of exercise 5.1 *(Class 10 Maths exercise 5.1)* you have studied the following points:

- An arithmetic progression (AP) is a list of numbers in which each term is obtained by

adding a fixed number d to the preceding term, except the first term. The fixed number d

is called the common difference.

The general form of an AP is a, a + d, a + 2d, a + 3d, . . . - In an AP with first term a and common difference d, the nth term (or the general term) is

given by an= a + (n – 1) d. - The sum of the first n terms of an AP is given by : S=n/2[2a+(n-1)d].
- If l is the last term of the finite AP, say the nth term, then the sum of all terms of the AP

is given by : S=n/2(a + l). - If a, b, c are in AP, then b=(a + b)/2 and b is called the arithmetic mean of a and c.

*NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.1 (Class 10 Math Ex. 5.1).*

*NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.1 (Class 10 Math Ex. 5.1).*

*NC**ERT** Solutions for Class 10 Maths Chapter 4 Quadratic Equations*

*NC*

*ERT*

*Solutions for Class 10 Maths Chapter 4 Quadratic Equations*

**NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations of exercise 4.1***(Class 10 Ex. 4.1)* for all boards. We have updated all the contents for the new academic session 2020-2021.

*(Class 10 Ex. 4.1)*for all boards

You can download this PDF for free and start your preparation to get maximum marks in upcoming and Board examinations. **Gicsu** **NCERT** Solution

**(Math Class 10 Ex. 4.1) ** PDF helps you in your preparation with exercise differentiation so that you can read each chapter more easily and can come back to any chapter again if necessary.

## NCERT Solutions for Class 10 Maths (Introduction)

**Pair of Linear Equations in Two Variables of exercise 4.1 ( ***Maths Class 10 ex 4.1*) you have studied the following points:

*Maths Class 10 ex 4.1*)

- A quadratic equation in the variable x is of the form ax² + bx + c = 0, where a, b, c are real numbers and a ≠ 0.
- A real number α is said to be a root of the quadratic equation ax²+ bx + c = 0, if aα²+ bα + c = 0. The zeroes of the quadratic polynomial ax²+ bx + c and the roots of the quadratic equation ax²+ bx + c = 0 are the same.
- If we can factorise ax²+ bx + c, a ≠ 0, into a product of two linear factors, then the roots of the quadratic equation ax²+ bx + c = 0 can be found by equating each factor to zero.
- A quadratic equation can also be solved by the method of completing the square.
- A quadratic equation ax²+ bx + c = 0 has: (i) two distinct real roots, if b²– 4ac > 0, two equal roots (i.e., coincident roots), if b²– 4ac = 0, and (iii) no real roots, if b²– 4ac < 0.